Diesel Cycle

Air-standard analysis of the compression-ignition (diesel) engine. Heat added at constant pressure via fuel injection. γ = 1.4, T₁ = 300 K.

Compression ratio r18
Cutoff ratio rco2.5

Engine States

State 1→ compressState 2→ injectState 3→ expandState 4→ exhaust
1→2 Isentropic compression
(all valves closed)
2→3 Constant-pressure heat addition
(fuel injected at TDC)
3→4 Isentropic expansion
(power stroke)
4→1 Constant-volume heat rejection
(exhaust blowdown)

Cycle Diagrams

1→2 Isentropic compression
2→3 Isobaric heat addition (fuel injection)
3→4 Isentropic expansion
4→1 Isochoric heat rejection
Volume V (norm.)0100k5.8MPressure P (Pa)1234P–V Diagram
0460921Entropy s (J/kg·K)4001k2kTemperature T (K)1234T–S Diagram
0460921Entropy s (J/kg·K)0700k2.1MEnthalpy h (J/kg)1234H–S Diagram

State Properties

StateT (K)P (kPa)V (norm.)s (J/kg·K)h (kJ/kg)
1300101.31.00000.0
29535795.60.0560656.6
323835795.60.1399212093.7
41082365.51.000921785.9
Thermal efficiency η = 60.9%= 1 − (rcoγ−1) / [γ(rco−1) · rγ−1]

Key Relations

Thermal efficiency
η = 1 − (rcoγ−1) / [γ·(rco−1)·rγ−1]
Isobaric heat addition (2→3)
Qin = cp(T₃−T₂)  |  rco = V₃/V₂ = T₃/T₂
Isentropic compression
T₂/T₁ = rγ−1  |  P₂/P₁ = rγ
vs Otto at same r
ηDiesel < ηOtto (higher Qin compensates)